From the above experiment it was evident that sodium hydroxide can be effectively standardized by using oxalic acid. E. CALCULATION 1. 3. 3.3.2 Standardization of NaOH solution using diprotic acid (oxalic acid) or (Succinic acid) Place the standard oxalic acid solution 0.025 M in the burette. Transfer 10 mL of the NaOH solution into a 125 mL conical flask with the aid of a pipette, add 1-2 drops of phenolphthalein indicator and titrate with the standard oxalic acid. Therefore, the equivalent weight of crystalline oxalic acid = 63. Calculation N 1 V 1 = N 2 V 2 N 2 =Normality of oxalic acid N 1 =Normality of NaOH V 2 =Volume of Oxalic acid V 1 =Volume of NaOH N 1 =N 2 V 2 /V 1. This is also the case for the standardization of NaOH with standard HCl. NaOH of unknow concentration. Calculations : 24,4 ml - 12 ml = 12,4 ml ⇒ Neutral. Weight out 0.4g of KHP The reaction between solutions of HCl and NaOH is illustrated by Equation 1. Top it up to the mark. Before you can use the NaOH(aq) to standardize your HCl(aq), you will have to standardize the NaOH(aq) using the primary solid acid standard, potassium hydrogen phthalate. THIS IS THE VALUE THAT YOU WILL USE IN EXPERIMENT 12B. STOPPER AND SAVE YOUR NaOH SOLUTION FOR USE IN EXPERIMENT 12B !!!!! (2) Again fill the burette with the standardized NaOH solution to the zero mark. CONCLUSION. You might think that you could just weigh 4.000g of solid NaOH and dissolve it in enough water to make 1.000 L of solution. Calculate the average molar concentration of the sodium hydroxide solution. In this experiment, standardization of a NaOH solution will be carried out either using KHP as the primary standard or by using a standard HCl solution of known concentration. 37 - 24,4 = 12,4 into the acid HCL been standardized. 4.000 g is after all 0.1000 mole of NaOH, so dissolving it in one litre of water should produce a one litre solution. The volumetric analysis allows for the calculation of the unknown amount or concentration by a reaction with a known amount of reagent. This sample calculation uses the … Equipment/Materials: Try it risk-free for 30 days Try it risk-free Ask a question. PROCEDURE (B): TITRATION OF STANDARDIZED NaOH AGAINST 12M HCL (1) Prepare 500ml of about 0.1M HCL from the concentrated HCL available in the laboratory by pipetting 4.2ml of the acid solution into a graduated cylinder. Suppose that you needed a 0.1000 M solution of NaOH to do a titration. Average NaOH molarity calculated to be 0.09515 M. Titrations performed by Yu-Ting Tseng and taken for comparison The standard deviation for both data sets was calculated by the method shown below using Equation 1. 2. Become a member and unlock all Study Answers. Calculate the molar concentration of the sodium hydroxide solution using your data for each run. 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